Question to Cache::Memcached

[Evan Martin]

On Tue, Jun 08, 2004 at 11:06:23AM -0700, Brad Fitzpatrick wrote:
> Can you change it to this:
> 
>  $hash = ($hash*33 + ord($_)) % (2 ** 31);
> 
> That should work, right?  *scratchs head*

Or maybe
  unpack('L', pack('L', $hash*33 + ord($_)))
to avoid division?

I could've sworn Perl exposed its internal hash function that it uses
for its own hashes--I think the similar languages do.

-- 
Evan Martin
martine@danga.com
http://neugierig.org